Unfortunately.......when we have one equation with multiple unknowns, we will have infinite solutions...
[ X * ( 4 + Z) ] / Y + 6 = 8
If we let X = 1 , Y = 2 and Z = 0 ....... this will solve the problem
If we let X = 2, Y = 4 and Z = 0 ........this will also solve the problem
And we could extract as many solutions as we wanted to by choosing appropriate values for all three variables......!!!!!!
Does X = 2, Y = 5, and Z = 1?
(answeryes or no)
(posted by person who made question)
Unfortunately.......when we have one equation with multiple unknowns, we will have infinite solutions...
[ X * ( 4 + Z) ] / Y + 6 = 8
If we let X = 1 , Y = 2 and Z = 0 ....... this will solve the problem
If we let X = 2, Y = 4 and Z = 0 ........this will also solve the problem
And we could extract as many solutions as we wanted to by choosing appropriate values for all three variables......!!!!!!