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On the Cartesian plane, the midpoint between two points A(a,b) and B(c,d) is M(m,n) . If A is moved vertically upwards 20 units and horizontally to the right 14 units, and B is moved vertically downwards 4 units and horizontally to the left 2 units, then the new midpoint between A and B is M. What is the distance between M and M ?

 Dec 29, 2017

Best Answer 

 #1
avatar+9488 
+1

M  =  midpoint of  (a, b)  and  (c, d)   =(a+c2,b+d2)

 

M'  =  midpoint of  (a+14, b+20)  and  (c-2, d-4)   =((a+14)+(c2)2,(b+20)+(d4)2) =(a+c+122,b+d+162) =(a+c2+122,b+d2+162) =(a+c2+6,b+d2+8)

 

 

distance between  M  and  M'   =(difference in x values)2+(difference in y values)2 =62+82 =100 =10

 Dec 29, 2017
 #1
avatar+9488 
+1
Best Answer

M  =  midpoint of  (a, b)  and  (c, d)   =(a+c2,b+d2)

 

M'  =  midpoint of  (a+14, b+20)  and  (c-2, d-4)   =((a+14)+(c2)2,(b+20)+(d4)2) =(a+c+122,b+d+162) =(a+c2+122,b+d2+162) =(a+c2+6,b+d2+8)

 

 

distance between  M  and  M'   =(difference in x values)2+(difference in y values)2 =62+82 =100 =10

hectictar Dec 29, 2017
 #2
avatar+847 
+3

Wow! Very nice, hectictar! 

 Dec 29, 2017

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