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Chords $\overline{WY}$ and $\overline{XZ}$ of a circle are perpendicular. If $XV = 4$, $WV = 3$, and $VZ = 9$, then find $YZ$.

 Sep 9, 2017
 #1
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By the theory of intersecting chords.....

 

XV * ZV  =  WV * YV     ....so....

 

4 * 9  =  3 * YV       divide both sides by 3

 

[ 4 * 9 ]  / 3  =   YV

 

36 / 3  =  YV   =  12

 

And since the chords are perpendicular, by the Pythagorean Theorem.......

 

ZV^2 + YV^2  = YZ^2

 

9^2  +  12^2 = YZ^2

 

225   =  YZ^2        take the square root of both sides

 

15  =  YZ 

 

 

cool cool cool

 Sep 9, 2017

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