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How do I find Ln(-1) ?

 Oct 4, 2015

Best Answer 

 #2
avatar+33665 
+4

Noting that e^(i*pi) = -1 then Ln(-1) is Ln(e^(ipi))  so that Ln(-1) = i*pi  

 Oct 4, 2015
 #1
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How do I find Ln(-1) ?

               

0 + -1.570796326i

 Oct 4, 2015
 #2
avatar+33665 
+4
Best Answer

Noting that e^(i*pi) = -1 then Ln(-1) is Ln(e^(ipi))  so that Ln(-1) = i*pi  

Alan Oct 4, 2015
 #3
avatar
+5

Ln(z) = Ln r + i theta (in terms of polar coordinates)

here r = 1. Theta = pi therefore...

--> Ln(-1) = Ln 1 + i*pi

                = 0 + i*pi = i*pi

 Oct 4, 2015

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