+0  
 
0
90
1
avatar+8 

 

 

 

 

 

 

 

does anyone know how to solve these

 

 

 

 

nellycrane  Sep 29, 2018
 #1
avatar+2295 
+1

Hi, nellycrane!

 

I think you will be better off if I give you an easier problem like \(x^2-4 \) . You are probably well aware that this is a difference of squares. \((x+2)(x-2)\) would be the corresponding factorization. 

 

Now, let's say that you want to factor \(x^2-30\) . This is not possible if you restrict yourself to the rational number set. However, it can be factored as \((x+\sqrt{30})(x-\sqrt{30})\)

 

In general, \(a^2-b^2=\left(\sqrt{a}+\sqrt{b}\right)\left(\sqrt{a}-\sqrt{b}\right)\) . You can apply this knowledge to the problems at hand.

 

\(x^2+50\\ a=x^2,b=-50;\\ (\sqrt{a}+\sqrt{b})(\sqrt{a}-\sqrt{b})\\ (\sqrt{x^2}+\sqrt{-50})(\sqrt{x^2}-\sqrt{-50}) \)

 

You can simplify this to get the factorization amongst the complex numbers. Good luck!

TheXSquaredFactor  Sep 30, 2018

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