Compute the range of the function $f(x) = \sqrt{x^2}$.
f(x) simplifies to x, so the range is all real numbers.
In interval notation, (-inf,inf).
The domain is all real numbers
The range is all real numbers greater or equal to 0
Could there also be some complex numbers involved here?
Note that sqrt (x^2) can be defined as l x l
The range of this function is [ 0, inf)