the perimiter of a rectangle is 42m. the length is 9m less than 2 times the width.
a. find the length and wodth of the rectangle
b. find the area of the rectangle
+130511 P = 2(L + W) → L + 9 = 2W
42 = 2L + 2W
42 = 2L + [ L + 9] simplify
42 = 3L + 9 subtract 9 from both sides
33 = 3L divide both sides by 3
11 = L
And 2W = L + 9
So 2W = 11 + 9
2W = 20 divide both sides by 2 and W = 10
So L = 11 and W = 10
And the area = L *W = (11) (10) = 110 units^2
