consider the line L : kx+3y+12=0 , where k is a constant
i)find k if L is parallel to 6x-y-7=0
ii)find k if L is perpendicular to 6x-y-7=0
+130544 consider the line L : kx+3y+12=0 , where k is a constant
i)find k if L is parallel to 6x-y-7=0
ii)find k if L is perpendicular to 6x-y-7=0
Putting the first line in slope-intercept form ,we have
y = (-k/3)x - 4
The second line, in the same form, is :
y = 6x - 7
Since parallel line have the same slope
-k/3 = 6 so k = -18
And perpendicular lines have negative reciprocal slopes, so
3/k = 6 and k = 1/2
+130544 consider the line L : kx+3y+12=0 , where k is a constant
i)find k if L is parallel to 6x-y-7=0
ii)find k if L is perpendicular to 6x-y-7=0
Putting the first line in slope-intercept form ,we have
y = (-k/3)x - 4
The second line, in the same form, is :
y = 6x - 7
Since parallel line have the same slope
-k/3 = 6 so k = -18
And perpendicular lines have negative reciprocal slopes, so
3/k = 6 and k = 1/2
