+0  
 
0
86
1
avatar

Container A and container B have leaks. Container A has 800 ml of water and is leaking 6 ml per minute. Container B has 1000 ml and is leaking 10 ml per minute. Let m represest the number of minutes the contains are leaking. How many minutes, m, will it take for the two containers to have the same amount of water? Write and solve an equation to show your work.

 Sep 30, 2020
 #1
avatar
0

800 - 6m =1000 - 10m, solve for m

 

m = 50 minutes - when both containers will have the same amount of water.

 

800 - (6*50) =1000 - (10*50)

 

500 ml           = 500 ml. Both containers will have 500 ml of water left after 50 minutes.

 Sep 30, 2020

15 Online Users