A line with slope of -3 intersects the positive x-axis at A and the positive y-axis at B. A second line intersects the x-axis at (8,0) and the y-axis at D. The lines intersect at (4,4) . What is the area of the shaded quadrilateral OBEC?
BA = (4, 4) with slope of -3.
y = -3x + 16
OB = 16
DC = points (4, 4) and (8, 0)
y = -x + 8
OD = 8
DOC = 8*8/2 = 32
BDE = 8*4/2 = 16
16+32 = 48 :)
=^._.^=
