The area of rectangle ABCD with vertices A(0, 0), B(0, 4), C(x, 4) and D(x, 0) is 32 square units. If x > 0, what is the value of x?
The area of rectangle ABCD with vertices A(0, 0), B(0, 4), C(x, 4) and D(x, 0) is 32 square units. If x > 0, what is the value of x?
Corner A is at the origin. Corner B is 4 units up, so the height of the rectangle is 4.
Since the height of the rectangle is 4, then, for the area to be 32, its width must be 8.
So, x = 8 Specifically, corner C is at (8,4) and corner D is at (8,0).
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