web2.0calc
 
+0  
 

 counting problem

0
401
2
avatar

Carla has 10 coins, each of which is a nickel, a dime, or a quarter. The total value of her coins is less than $1.00. How many differentcombinations of coins might Carla have?
Note: The values of a nickel, a dime, and a quarter are, respectively, $0.05, $0.10, and $0.25.

 Aug 21, 2020

2+0 Answers

 #1
avatar
+1

       n   d    q

1  = 9   5   0  
2  = 7   6   0  
3  = 5   7   0  
4  = 3   8   0  
5  = 1   9   0  
6  = 10   2   1  
7  = 8   3   1  
8  = 6   4   1  
9  = 4   5   1  
10  = 2   6   1  
11  = 0   7   1  
12  = 9   0   2  
13  = 7   1   2  
14  = 5   2   2  
15  = 3   3   2  
16  = 1   4   2  
17  = 4   0   3  
18  = 2   1   3  
19  = 0   2   3  
 

 Aug 21, 2020
 #2
avatar
+1

Sorry, I didn't see that has only "10" coins! Forget about the above list. I can only see 3 combinations:

 

1  = 1   9   0  
2  = 4   5   1  
3  = 7   1   2  
 

Guest Aug 21, 2020

1 Online Users

Top Users

avatar+37159 ElectricPavlov
avatar+33659 Alan moderator
avatar+15001 asinus moderator
avatar+9673 MaxWong
avatar+2669 LiIIiam0216
avatar+2490 GingerAle
avatar+1897 NotThatSmart
avatar+1839 ABJeIIy
avatar+1768 bader
avatar+1533 parmen
avatar+1443 blackpanther

Sticky Topics