Hi MWizzard, I think you still wanted me to do this problem. :)
I did c first.
c)
Volume of air = \(1333\frac{1}{3}cm^3\)
and that is 2/3 of the total volume so
the total volume has to be \(1333\frac{1}{3}\times \frac{3}{2} = 2000cm^3=2L\)
a)
20*10*h=2000
so
h=10cm
b)
volume of the water = \(2000-1333\frac{1}{3} = 666\frac{2}{3}ml \)
c)
I already did 2L
d)
If you pump air in it will still take up the same amount of space because the water will not compress, just the air pressure will become greater. So when you take out the 200ml of water the air will just expand to take up the space.
Air will take the space of
\(1333\frac{1}{3}+200=1533\frac{1}{3}cm^3\)
Note: 1cm^3=1ml