**I did 1. and 2., but how do i go about entering the values for 3.? Its been a while so i kind of forgot some algebra rules.**

Veteran
Apr 10, 2017

#1**+1 **

[ 3 / [(x + h) + 2] - 3/ [ x + 2] ] / h get a common denominator

[ (3 [x + 2] - 3 [ (x + h) + 2 ] ] / [ h (x + h + 2) (x + 2)] simplify

[ 3x + 6 - 3x - 3h - 6 ] / [ h (x + h + 2) (x + 2) ]

[ -3h] / [ h (x + h + 2) (x + 2) ] the "h's" cancel

[-3] / [ (x + h + 2) (x + 2) ]

Take the limit as h → 0

[-3] / [ (x + 2) ( x + 2) ] =

-3 / (x + 2)^{2}

CPhill
Apr 10, 2017