+0  
 
-1
112
2
avatar+223 

I did 1. and 2., but how do i go about entering the values for 3.? Its been a while so i kind of forgot some algebra rules.

Veteran  Apr 10, 2017
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2+0 Answers

 #1
avatar+75279 
+1

 

[ 3 / [(x + h) + 2]   -  3/ [ x + 2]  ]   /  h          get a common denominator

 

[ (3 [x + 2]  - 3 [ (x + h) + 2 ] ] /  [ h (x + h + 2) (x + 2)]       simplify

 

[ 3x + 6  - 3x - 3h - 6 ] /  [ h (x + h + 2) (x + 2) ]

 

[ -3h] /  [ h (x + h + 2) (x + 2) ]      the "h's" cancel

 

[-3] /  [  (x + h + 2) (x + 2) ]

 

Take  the limit  as h → 0

 

[-3] / [ (x + 2) ( x + 2) ]  =

 

-3 / (x + 2)2 

 

 

cool cool cool

CPhill  Apr 10, 2017
 #2
avatar+223 
0

thank you

Veteran  Apr 10, 2017

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