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The mass of the bucket B is 180 kg. From 𝑑 = π‘œ to 𝑑 = 2 s, the x and y coordinates of the center of mass of the bucket are

π‘₯ = βˆ’0.2𝑑3 + 0.06𝑑2 + 10 π‘š

𝑦 = 0.1𝑑2 + 0.4𝑑 + 6 π‘š

a.) Determine the x component of the force exerted on the bucket by its supports

at 𝑑 = 1𝑠.

b.) Determine the y component of the force exerted on the bucket by its supports

at 𝑑 = 1𝑠.

 May 12, 2020
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x = -0.2t3 + 0.06t2 + 10 [m] 
vx = x' = -0.6t2 + 0.12t [m/s]
ax = vx' = -1.2t + 0.12 [m/s2]
ax(1) = -1.08 m/s2

Ξ£Fx = max = (180kg)(-1.08m/s2) = -194.4N

y = 0.1t+ 0.4t + 6 [m]
vy = y' = 0.2t + 0.4 [m/s]
ay = vy' = 0.2 [m/s2]

Ξ£Fy = may = (180kg)(0.2m/s2 + 9.8m/s2) = 1800N

 May 12, 2020

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