The mass of the bucket B is 180 kg. From π‘ = π to π‘ = 2 s, the x and y coordinates of the center of mass of the bucket are
π₯ = β0.2π‘3 + 0.06π‘2 + 10 π
π¦ = 0.1π‘2 + 0.4π‘ + 6 π
a.) Determine the x component of the force exerted on the bucket by its supports
at π‘ = 1π .
b.) Determine the y component of the force exerted on the bucket by its supports
at π‘ = 1π .
+154 x = -0.2t3 + 0.06t2 + 10 [m]
vx = x' = -0.6t2 + 0.12t [m/s]
ax = vx' = -1.2t + 0.12 [m/s2]
ax(1) = -1.08 m/s2
Ξ£Fx = max = (180kg)(-1.08m/s2) = -194.4N
y = 0.1t2 + 0.4t + 6 [m]
vy = y' = 0.2t + 0.4 [m/s]
ay = vy' = 0.2 [m/s2]
Ξ£Fy = may = (180kg)(0.2m/s2 + 9.8m/s2) = 1800N
