emergency

You don't have a matching number of brackets!  However, I've made an assumption below (and also assumed you are only dealing with real numbers so that D is positive).

\(\\ 3.00222\times10^{-9}=D\times |\ln{(2\times10^{-7})\times D^{0.5}}|\\\\ 3.00222\times10^{-9}=D\times |(\ln2+\ln{10^{-7}})\times D^{0.5}|\\\\ 3.00222\times10^{-9}=D\times |(\ln2-7\ln{10})\times D^{0.5}|\\\\ D^{1.5}=3.00222\times10^{-9}/|(\ln2-7\ln{10})|\\\\ D=(3.00222\times10^{-9}/|(\ln2-7\ln{10})|)^{2/3}\)

Sorry about that; Could you please solve this? Now brackets are right:)

3.00222*10^(+9)= (D)*abs[ln(2*10^(-7))*sqrt(D)]

D=?

Well, again assuming that D is real and positive (if it were negative we'd have a complex number for sqrt(D)), the result is as I gave above, except that the 10^-9 in the numerator becomes 10⁺⁹.

I should perhaps add that the vertical lines refer to taking the absolute value of whatever is the result of what is between them.  If you need a numerical result, you can use the calculator on the home page here. 

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3.00222*10^(+9)= (D)*abs[ln(2*10^(-7))*sqrt(D)]

D=?

Please pay attention that abs[ln(2*10^(-7))*sqrt(D)]

I could not solve by using the calculator because of the inside of squared brackets! 

3.00222*10^(+9)= (D)*abs([ln(2*10^(-7))*sqrt(D)])

D=?

If D is positive we have the result as I've given above (with 10⁹ not 10^-9).  If D is negative, then srqt(D) = sqrt(|D|)*i, where i is sqrt(-1). The terms inside the absolute value then become, say k*i, where k is a real number.  The absolute value of k*i is given by sqrt(k²), namely just k. so |ln(...)sqrt(D)| =|ln(...)|*sqrt(|D|).  D can't be negative though, because if it were we would have D*|ln(...)|*sqrt(|D|) = - |D|*|ln(...)|*sqrt(|D|) = a negative number; but the LHS is a positive number, so D must be positive.

Here's a graph calculated by Mathcad (which is quite happy with imaginary numbers) for a range of values of D:

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Please solve ln(2*10^(-7)*sqrt(D))