What is the equation of the line that passes through the point (-1,-7) and has a slope of 2
We can use the form y=mx+b to solve this problem, where m is the slope and b is the y-intercept.
Since the slope is given as 2, we can substitute this into the equation:
y = 2x+b
Now, we can manipulate the point (-1,-7) to be in the form of a y-intercept - (0, y).
Note that a slope of 2 = 2/1, which means the rise = 2(which is added to the y) and run = 1(which is added to the x).
Adding this to our point of (-1,-7), we get:
((-1+1),(-7+2)) = (0, -5)
Therefore -5 is our y-intercept.
Now, substituting -5 into our equation, we get:
y = 2x + -5
y = 2x - 5