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4010
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Evaluate 21+27+33+...+999.

 Aug 4, 2016

Best Answer 

 #4
avatar
+5

http://www.wolframalpha.com/input/?i=%E2%88%91%5B21%2B6n%5D,+n%3D0+to+163

=83,640

 Aug 4, 2016
 #1
avatar+33653 
0

 21+27+33+...+999 → 15 + 6*(1 + 2 + 3 + ... + 164)  →  15+6*164*(164+1)/2 →  81195

.

 Aug 4, 2016
 #2
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0

21+27+33+999=1,080

 Aug 4, 2016
 #3
avatar+33653 
0

Look at the ... between the 33 and the 999 !

Alan  Aug 4, 2016
 #4
avatar
+5
Best Answer

http://www.wolframalpha.com/input/?i=%E2%88%91%5B21%2B6n%5D,+n%3D0+to+163

=83,640

Guest Aug 4, 2016
 #5
avatar+33653 
0

Oops!  You are right.  I left out 15*163

 

81195 + 15*163 = 83640

.

Alan  Aug 4, 2016
 #6
avatar+129840 
+5

The number of terms, n   = [999 - 21] / 6 + 1  = 164

 

And the sum is given by :

 

(n /2) (a1 + a164)         where a1 = 21 and a164 = 999

 

(164)/2  *  (21 + 999)  =  83,640

 

 

 

cool cool cool

 Aug 4, 2016

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