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If \(f(x) = 8x^3 - 6x^2 + 12x - 0\), what is the value of \(f\left(\dfrac{3}{4}\right)\)?

 Apr 12, 2021

Best Answer 

 #1
avatar+493 
+5

Well fill in 3/4 every time you see x.

\(8\cdot \frac{3}{4}^3-6\cdot \frac{3}{4}^2+12\cdot \frac{3}{4}-0\)

\(=9\)

 Apr 12, 2021
 #1
avatar+493 
+5
Best Answer

Well fill in 3/4 every time you see x.

\(8\cdot \frac{3}{4}^3-6\cdot \frac{3}{4}^2+12\cdot \frac{3}{4}-0\)

\(=9\)

mworkhard222 Apr 12, 2021

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