If \(f(x) = 8x^3 - 6x^2 + 12x - 0\), what is the value of \(f\left(\dfrac{3}{4}\right)\)?
Well fill in 3/4 every time you see x.
\(8\cdot \frac{3}{4}^3-6\cdot \frac{3}{4}^2+12\cdot \frac{3}{4}-0\)
\(=9\)
Well fill in 3/4 every time you see x.
\(8\cdot \frac{3}{4}^3-6\cdot \frac{3}{4}^2+12\cdot \frac{3}{4}-0\)
\(=9\)