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# Evaluating Functions

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If $$f(x) = 8x^3 - 6x^2 + 12x - 0$$, what is the value of $$f\left(\dfrac{3}{4}\right)$$?

Apr 12, 2021

#1
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Well fill in 3/4 every time you see x.

$$8\cdot \frac{3}{4}^3-6\cdot \frac{3}{4}^2+12\cdot \frac{3}{4}-0$$

$$=9$$

Apr 12, 2021

#1
+104
+5
$$8\cdot \frac{3}{4}^3-6\cdot \frac{3}{4}^2+12\cdot \frac{3}{4}-0$$
$$=9$$