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f sinθ=3/5,where 0°

 Aug 12, 2020
 #1
avatar+1039 
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I'm have trouble understanding: "where 0". Could you please clarify? Thanks!

 Aug 12, 2020
 #2
avatar+31340 
+2

I suspect this question should read something like:

 

If sinθ=3/5, find θ, where 0º < θ < 360º  (or, perhaps, some other upper limit on θ).

 Aug 12, 2020

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