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Hello. How would I factor the following?

7(x-1)-x(x+1)

a2-36

b2+5b+6

 

Thank you!

Guest Mar 5, 2017
 #1
avatar+26753 
+5

 

a2-36  

This is a standard difference of two squares so: a2 - 36 → a2 - 62 →  (a+6)(a-6)

 

b2+5b+6  →  (b + 2)(b + 3)

 

7(x-1)-x(x+1) doesn't factor nicely at all as far as I can see! 

.

Alan  Mar 5, 2017
 #2
avatar+92806 
0

For questions like 

\(b^2+5b+6\)

 

you need to look for 2 numbers that multiply to be +6

Since it is + they both must be + or both -

BUT

they have to add to be +5  so they both must be +

 

ok

we have 

1*6=6   but 1+6 is not 5

2*3=6   and  2+3=5        BINGO!

so we have

\(b^2+5b+6=(b+2)(b+3)\)

 

Just like Alan said :)))

Melody  Mar 5, 2017

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