\({5x^{2} + 6xy - 8y^{2}}\)
this is a perfect square, so i know:
\({{(a + b)^{2} = a^{2} + 2ab + b^{2}}}\)
just how would i factor this though? i'm completely lost :-(
Break the expression into groups:
(5x^2-4xy) + (10xy-8y^2).
Factor out x and 2y respectively:
x(5x-4y) + 2y(5x-4y).
Factor out common term:
(x+2y)(5x - 4y) <---- Answer
where did -4xy & 10xy come from?
i guess you can think of it in the form: ax2+bx+c instead of ax2+bxy+c2 then, factor the resulting quadratic using your methods
