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\({5x^{2} + 6xy - 8y^{2}}\)

this is a perfect square, so i know:

\({{(a + b)^{2} = a^{2} + 2ab + b^{2}}}\)

 just how would i factor this though? i'm completely lost :-(

 Jul 4, 2018
 #1
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Break the expression into groups:

(5x^2-4xy) + (10xy-8y^2).

 

Factor out x and 2y respectively:

x(5x-4y) + 2y(5x-4y).

 

Factor out common term:

(x+2y)(5x - 4y) <---- Answer

 Jul 4, 2018
 #2
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where did -4xy & 10xy come from?

Guest Jul 4, 2018
 #3
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i guess you can think of it in the form:
ax2+bx+c instead of ax2+bxy+c2

then, factor the resulting quadratic using your methods

ChowMein  Jul 4, 2018

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