Factoring

Thank you!

There's no "factoring"  involved, Shades......but we can express it in a more simple form.....

2sin^2x - 1   =

2sin^2x  - [ sin^2x + cos^2x]  =

sin^2x  - cos^2x =

-cos(2x)

Actually....if we wanted to stretch a point...it could be factored as:

 [ √2sinx + 1 ]   [ √2sinx - 1 ]

However.....I assumed you wanted to "simplify"  it rather than "factor"  it......