Find t when 9.75t^2 + 1.8t = 0

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Guest Mar 21, 2015

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Best Answer

t is common to both terms so you can write: t(9.75t + 1.8) = 0

This mean that either t = 0 or t = -1.8/9.75

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Alan Mar 21, 2015

Alan · Answer 1 · 2015-03-21T08:53:11

t is common to both terms so you can write: t(9.75t + 1.8) = 0

This mean that either t = 0 or t = -1.8/9.75

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Guest · Answer 2 · 2015-03-21T06:49:21

If you graph it you can see immediately that y=0 at 0 and-0.1846