Find the equation of a polynomial f(x) of degree 5 with zeros: x=200, x=100, x=0, x=-100, x=-200 and f(5)=5. Show what the maxiums and minimums are. Please show each step and graph with all zero points and maxium and minimum points labeled.
Given that f(5)=5 and it crosses y=0 at the following points:
x=200,x=100,x=0,x=−100,x=−200
Since the crossing points of this function is rational, I deduct that the function is factorizable.
Perform reverse-factorization:
The function need to be in this form:
g(x)=(x+200)(x+100)(x+0)(x−100)(x−200)
For it to have roots at x=200,x=100,x=0,x=−100,x=−200
There are a total of five zero-points at:
1.x=−200,y=0
2.x=−100,y=0
3.x=0,y=0 (Origin)
4.x=100,y=0
5.x=200,y=0
There are a total of four critical points at:
Local Maxima:
1.x=√15000−1000√145,y=200000000(√5+5√29)√30−2√145
2.x=−√15000+1000√145,y=−200000000(√5−5√29)√30+2√145
Local Minima:
3.x=√15000+1000√145,y=(√5−5√29)√30+2√145
4.x=−√15000−1000√145,y=−200000000(√5+5√29)√30−2√145
Since f(5)=5, Just divide every y-value of maximas and minimas above by a factor of g(5)/5=398750625
f(x)=1398750625(x+200)(x+100)x(x−100)(x−200)
Q.E.D.
(I bet you just randomly typed the numbers in, didn't you? (Because the x and y values are pretty ugly to be honest))
I did just type in the numbers. :D. By the way, not to sound criticizing, you did not graph the answer as per the question.