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25 ∑(3k+1/4) k=1

 May 23, 2014

Best Answer 

 #1
avatar+33663 
+5

$$Do you mean $\sum_{k=1}^{25}(3k+\frac{1}{4})$?\\
\\
If so, then this can be written as $$3\sum_{k=1}^{25}k+\sum_{k=1}^{25}\frac{1}{4}$$\\\\
This becomes $$3*\frac{25(25+1)}{2}+25*\frac{1}{4}$$\\
$$ = 975+6\frac{1}{4}$$
$$ = 981\frac{1}{4}$$

.
 May 23, 2014
 #1
avatar+33663 
+5
Best Answer

$$Do you mean $\sum_{k=1}^{25}(3k+\frac{1}{4})$?\\
\\
If so, then this can be written as $$3\sum_{k=1}^{25}k+\sum_{k=1}^{25}\frac{1}{4}$$\\\\
This becomes $$3*\frac{25(25+1)}{2}+25*\frac{1}{4}$$\\
$$ = 975+6\frac{1}{4}$$
$$ = 981\frac{1}{4}$$

Alan May 23, 2014

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