Find the perimeter of a triangle given that the lengths of the sides are 3/8, 1/2 and 3/4
+9673 Add them up!!
\(\text{Perimeter}\\ =\dfrac{3}{8} + \dfrac{1}{2}+\dfrac{3}{4}\\ =\dfrac{3}{8} + \dfrac{1\times 4}{2\times 4}+\dfrac{3\times 2}{4\times 2}\\ =\dfrac{3}{8} + \dfrac{4}{8}+\dfrac{6}{8}\\ =\dfrac{3+4+6}{8}\\ =\dfrac{13}{8}\\ =1 \dfrac{5}{8}\\ =1.625\)
Last 3 rows are just the same. Depends on which one do your teacher prefer you to use.
