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# Find the perimeter of a triangle given that the lengths of the sides are 3/8, 1/2  and 3/4

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Find the perimeter of a triangle given that the lengths of the sides are 3/8, 1/2  and  3/4

Guest Apr 17, 2017
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#1
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3/8 + 1/2 + 3/4 is the same as 3/8 + 4/8 + 6?8. So, it is 13/8

liveevillevi  Apr 17, 2017
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$$\text{Perimeter}\\ =\dfrac{3}{8} + \dfrac{1}{2}+\dfrac{3}{4}\\ =\dfrac{3}{8} + \dfrac{1\times 4}{2\times 4}+\dfrac{3\times 2}{4\times 2}\\ =\dfrac{3}{8} + \dfrac{4}{8}+\dfrac{6}{8}\\ =\dfrac{3+4+6}{8}\\ =\dfrac{13}{8}\\ =1 \dfrac{5}{8}\\ =1.625$$