Find the vertex of the graph of the equation \(x -y^2 + 6y =8\).
Find the vertex of the graph of the equation . (It is a sideways parabola)
\(x-y^2+6y=8\\ x=y^2-6y+8\\ x=(y-4)(y-2)\\ \)
The roots are y=2 and y=4
The axis of symmetry is y=(2+4)/2 = 3
So y=3
x=(3-4)(3-2) = -1*1 = -1
The vertex is (-1,3)
Find the vertex of the graph of the equation ....
