Find three consecutive even numbers that sum to 66
$$\underbrace{(a_2-2)}_{=a_1}+a_2+\underbrace{(a_2+2)}_{=a_3}=66\\\\3a_2=66 \quad | \quad :3\\a_2=22\\a_1=a_2-2=22-2=20 \\a_3 = a_2+2=22+2=24\\\\20 + 22 + 24 = 66$$
20
22
24
