find what the number is for z

$\dfrac 1 9 z - 5 = \dfrac {7}{18} \\ \dfrac 1 9 z = \dfrac 7{18}+5 = \dfrac{7}{18}+\dfrac{90}{18} =\dfrac{97}{18}\\ z = 9\times \dfrac{97}{18} = \dfrac{97}{2}\\ z=\dfrac{97}{2}$

what is 1/9 times z minus 5 equals 7/18

1/9z - 5=7/18

1/9z=7/18  +5

1/9z=5 7/18

1/9z=97/18 multiply both sides by 9

z=873/18=48 1/2