what is 1/9 times z minus 5 equals 7/18
\(\dfrac 1 9 z - 5 = \dfrac {7}{18} \\ \dfrac 1 9 z = \dfrac 7{18}+5 = \dfrac{7}{18}+\dfrac{90}{18} =\dfrac{97}{18}\\ z = 9\times \dfrac{97}{18} = \dfrac{97}{2}\\ z=\dfrac{97}{2}\)
1/9z - 5=7/18
1/9z=7/18 +5
1/9z=5 7/18
1/9z=97/18 multiply both sides by 9
z=873/18=48 1/2
