Find c given that the expansion (1 + cx) (1 + x)^4 includes the term 22x^3.
(1 + cx) (1 + x)^4
Expanding (1+ x)^4 we have
(1 + 4x + 6x^2 + 4x^3 + x^4)
So (1 + cx)(1 + 4x + 6x^2 + 4x^3 + x^4) produces two x^3 terms, i.e. 4x^3 and 6cx^3
So
4 + 6c = 22 subtract 4 from both sides
6c = 18 divide both sides by 6
c = 3