first time post

These are good questions - welcome to web2.0calc forum :)

Any real number divided by itself = 1       except for 0       0/0  is undefined

So w/w = 1 so long as w is not equal to 0   

NOW

$$\\(-3)^2=-3*-3=9\\
but\\
-3^2=-1*3^2=-1=9=-9\\\\
$I know this is confusing but think about this question.$\\
20-3^2=20-9=11\\
$See how the - sign did not get squared ?$\\
$If I can help more or explain more let me know. $$$    

how do I know if w = 0. It is in a function, maybe at some points it equals 0.

For -3 squared, two negative is positive isn't it, even amount of powers is positive, uneven is odd

you have erros in your example

for n+(-1)squared i just6 take out the minus first?

when does it remain inside of the brackets

When is there a 1 put outside brackets?

I think your example doesnt work all the time. If I just always leave the negative out side, I will always get a negative answer for all powers. It cannot be right example.

ignore the last post. I thought but means different.

I don't know if all those anon posts are from the same person.  

It would be easier if your joined up and then I would know :)

Anyway I'll talk about it a little more

If there are no brackets then you DO NOT put any in.  The answer will be negative.

$$\\-6^2=-36\\
-x^2<0$$

The negative sign is ONLY squared if the brackets are there in the original question.

$$(-7)^2=49

(-x)^2>0 \qquad $always$$$

Does that help?

Thanks Chris