+0  
 
0
281
1
avatar

Solve floor(r) + r = 12.2 - r.

 May 2, 2022
 #1
avatar+9674 
+2

We have \(\lfloor r \rfloor = 12.2 - 2r\). Then 12.2 - 2r must be an integer. Then \(r = k + 0.1\text{ or }r = k + 0.6\) for some integer k. Now you can substitute that and try to solve it like a linear equation.

 May 2, 2022

3 Online Users

avatar