We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website. cookie policy and privacy policy.
 
+0  
 
0
42
3
avatar+673 

 

For the right triangle shown, what is the tangent of angle A?

 

A) 2/3

B) 3/2

C) 3/4

D) 4/3

E) 5/3

 

 

 

 

 

What is the perimeter of the figure in the diagram (round to three decimal places)?

 

A) 44.471

B) 35.046

C) 32.471

D) 27.758

E) 23.046

 

 

 

 

 

What is the area of the parallelogram?

 

A) 168 sq. inches

B) 140 sq. inches

C) 130 sq. inches

D) 120 sq. inches

E) 52 sq. inches

 Aug 28, 2019
 #1
avatar
+2

 

For the triangle problem, the triangle has to be a 3, 4, 5 triangle.

 

therefore, tangent A = opposite over adjacent = 3/4 = 0.75 

.

 Aug 28, 2019
 #2
avatar+103148 
+2

First one.....this is a 3-4-5 right triangle

x = 3     x + 1  = 4      x + 2  = 5

tan A  = BC/AB  = x / [ x + 1 ]  =  3 / 4

 

 

Second one....this is a little tough

We have a semi-circle  with a radius of 3

So....its perimeter  =  pi * 3   units

 

Then, we have a four sided figure

Two of sides have a length of 3  =   6   units

 

Let the bottom vertex of the figure lie at (0,0)

Then the bottom left vertex lies at  (-5, 2)

And the length of the bottom edge  =  sqrt (5^2 + 2^2)  = sqrt(29) units

 

And the bottom right vertex lies at  (1,2)

So...the length of the bottom right edge  = sqrt( 1^2 + 2^2)  = sqrt(5) units

 

So....the total perimeter  is    [ 3pi + 6 + sqrt(29) + sqrt(5) ]  = 23.046 units

 

Last one

 

Easy 

 

area  =  base * height  = 14 * 10   = 140 in^2

 

 

 

cool cool cool

 Aug 28, 2019
 #3
avatar
+1

1)  C

2)  E

3)  B

For a moment I felt that I'm in a 3rd grade again.smiley

 Aug 28, 2019

38 Online Users

avatar