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# For the right triangle shown, what is the tangent of angle A?

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3 For the right triangle shown, what is the tangent of angle A?

A) 2/3

B) 3/2

C) 3/4

D) 4/3

E) 5/3 What is the perimeter of the figure in the diagram (round to three decimal places)?

A) 44.471

B) 35.046

C) 32.471

D) 27.758

E) 23.046 What is the area of the parallelogram?

A) 168 sq. inches

B) 140 sq. inches

C) 130 sq. inches

D) 120 sq. inches

E) 52 sq. inches

Aug 28, 2019

#1
+2

For the triangle problem, the triangle has to be a 3, 4, 5 triangle.

therefore, tangent A = opposite over adjacent = 3/4 = 0.75

.

Aug 28, 2019
#2
+2

First one.....this is a 3-4-5 right triangle

x = 3     x + 1  = 4      x + 2  = 5

tan A  = BC/AB  = x / [ x + 1 ]  =  3 / 4

Second one....this is a little tough

We have a semi-circle  with a radius of 3

So....its perimeter  =  pi * 3   units

Then, we have a four sided figure

Two of sides have a length of 3  =   6   units

Let the bottom vertex of the figure lie at (0,0)

Then the bottom left vertex lies at  (-5, 2)

And the length of the bottom edge  =  sqrt (5^2 + 2^2)  = sqrt(29) units

And the bottom right vertex lies at  (1,2)

So...the length of the bottom right edge  = sqrt( 1^2 + 2^2)  = sqrt(5) units

So....the total perimeter  is    [ 3pi + 6 + sqrt(29) + sqrt(5) ]  = 23.046 units

Last one

Easy

area  =  base * height  = 14 * 10   = 140 in^2   Aug 28, 2019
#3
+1

1)  C

2)  E

3)  B

For a moment I felt that I'm in a 3rd grade again. Aug 28, 2019