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\(xy + 5y + 4x + 20=1\)

 Sep 13, 2020
 #1
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0

The possible values of y are -1 and -2.

 Sep 13, 2020
 #2
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+2

If   xy  =  - 4x       

        the equation devolves to something other than one  = 1

     xy = - 4x

      y = -4

 Sep 13, 2020

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