Alan, Ben and Carl shared some marbles. Alan had 1/3 of what Ben and Carl had. Ben had 1/5 of what Alan and Carl had. Alan had 24 fewer marbles than Carl. How many marbles did they have altogether?

Fritzizj Jul 11, 2021

#1**+1 **

Let Carl had X marbles

Marbles with Alan = X-24

Let marbles with ben = Y

Marbles with Alan = (X+Y)/3

X-24 = (X+Y)/3

3X-72 = X+Y

2X-Y= 72...(1)

Marbles with Ben =(2X-24)/5

5Y= 2X-24

2X-5Y= 24...(2)

Solving (1) & (2)

Y= 12

X= 42

Total marbles with Alan = 18

Total marbles with all of them = 12+18+42

= 72

apsiganocj Jul 11, 2021