Alan, one of the moderators might be able to help you in this physics question, but is not online right now.
I think your free body diagrams are like this (you'll need to fill in the distances yourself):
Correction: The top force for BE should say RE not RD
Another correction: In the free body diagram of AC the force RC is pointing up when it should be pointing down!
Because a free body diagram only considers the forces acting directly on the (free) body in question. The only force acting on AC from BE is RB
I think the following is probably what is needed (but you should check it carefully!).
Note: The force on top of BE should be labelled RE not RD (which was a typo by me). It will be the same in magnitude as RB.
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Yes Alan, you answer is correct.
But I still have some problems with the free body diagram.
1 - What is Rc ? is this the shear force ??
2- Is RE is the reaction of the support in beam BE ?
3- What is RB in the beam BE ?
those are my three questions and I will fully understand this problem.
1 - What is Rc ? is this the shear force ??
In the free-body diagram for CD, RC is the net force on CD due to AC (i.e. AC is helping to support CD and keep it from going down).
In the free-body diagram for AC, RC is the reaction of CD on AC (Newton's 3rd law of motion).
2- Is RE is the reaction of the support in beam BE ?
Yes, in free-body diagram BE, RE is the force of the support at E on BE.
3- What is RB in the beam BE ?
In free-body diagram BE, RB is the force of AC on BE (i.e. AC is trying to pull BE down).
In free-body diagram AC, RB is the reaction force of BE on AC (i.e. BE is trying to keep AC up - Newton's 3rd law again).
Hope this helps.