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What is angle PQR + angle PRS?

 

 Jan 15, 2021
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Let O  be the center of the  circle

 

Angles OQP  and ORP both =  90°

 

Then  in quadrilateral PQOR.....angle  QOR is supplemental to angle QPR  =140°

 

So   the smaller angle inscribed angle QSR    =    (360 -140)/2 =  220/2   = 110° 

 

And  the larger angle QSR = 360 - 110  =   250°

 

And  in quadrilateral  PQSR  the  sum of angles  PQS + PRS =   360  - 40 -250  =   

 

360  -  290  =

 

70°

 

cool cool cool

 Jan 15, 2021
edited by CPhill  Jan 15, 2021

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