(1) In triangle JKL, we have JK = JL = 25 and KL = 30. Find the area.

(2) In triangle ABC, we have AB = 5, AC = 12, BC = 13. Find the circumradius.

Guest May 1, 2022

#1**+1 **

1) Use Heron's formula: \(\sqrt{s(s-25)(s-25)(s-30)}\), where \(s = {{25 + 25 + 30} \over 2}\)

BuilderBoi May 1, 2022

#2**+1 **

2) Because we have a right triangle, we know the circumradius is half of the hypotenuse (longest side length). This means that the circumradius is \(\color{brown}\boxed{6.5}\)

BuilderBoi May 1, 2022