(1) In triangle JKL, we have JK = JL = 25 and KL = 30. Find the area.
(2) In triangle ABC, we have AB = 5, AC = 12, BC = 13. Find the circumradius.
+2666 1) Use Heron's formula: \(\sqrt{s(s-25)(s-25)(s-30)}\), where \(s = {{25 + 25 + 30} \over 2}\)
+2666 2) Because we have a right triangle, we know the circumradius is half of the hypotenuse (longest side length). This means that the circumradius is \(\color{brown}\boxed{6.5}\)
