In right triangle ABC (C = 90), the acute angles are in the ratio 5:1, i.e. BAC:ABC = 5:1. If CH is the altitude to AB and CL is the angle bisector of ACB, find HCL.
Angle A = 5/6(90) = 75
Angle ACH = 180 - 90 - ∠A = 15
Angle HCL = 45 - 15
∠HCL = 30º
