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In right triangle ABC (C = 90), the acute angles are in the ratio 5:1, i.e. BAC:ABC = 5:1.  If CH is the altitude to AB and CL is the angle bisector of ACB, find HCL.

 

 Mar 28, 2021
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Angle A = 5/6(90) = 75

Angle ACH = 180 - 90 - ∠A = 15

Angle HCL = 45 - 15

∠HCL = 30º

 Mar 29, 2021

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