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Let A, B, C be points on circle O such that AB is a diameter, and CO is perpendicular to AB. Let P be a point on OA, and let line CP intersect the circle again at Q. If OP = 20 and PQ = 8, find r^2, where r is the radius of the circle.

 

 Nov 22, 2021
 #1
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AO = BO = CO => r

 

AP * BP = CO * PQ

 

(r - 20)(r + 20) = 8 * [sqrt(r2 + 202)]

 Nov 23, 2021
 #2
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Corrections:::

 

Second line:    AP * BP = CP * PQ

Guest Nov 23, 2021

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