Altitudes AX and BY of acute triangle ABC intersect at H. If angle BAC = 43 degrees and angle ABC = 67 degrees, then what is angle AHC?
+14915 What is angle AHC?
Hello Guest!
Let the base points of the heights from corners A, B, C of the triangle be a, b, c.
\(ACH=90-CAB=90-43=47\\ HCB=ACB-ACH=70-47=23\\ CHb=90-ACH=90-47=43\\ CHa=90-HCB=90-23=67\\ AHC=180-CHa=180-67=113 \)
\(AHC=113°\)
The angle AHC is 113°.
!
