We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website. cookie policy and privacy policy.
 
+0  
 
0
64
1
avatar

Given are the lines l, m and n

l: 6x - 3y = 20

m: y = 2x - 6

n: 5x + 2 1/2y - 9 = 0

 

a. How are the lines l and m relative to each other?

b. How are the lines m and n relative to each other?

 Jun 8, 2019
 #1
avatar+102937 
+3

(a)

 

Rewrite l    as

 

-3y  = -6x + 20          divide through by -3

y = 2x - 20/3

 

m :  y = 2x - 6

 

Note that in the form  y = mx + b       m is the slope of the line

 

So   l and  m    have the same slope...so....they are parallel

 

 

(b)   5x + 2 1/2 y -9  = 0

5x + 5/2 y - 9  = 0               add 9 to both sides......subtract  5 x from both sides

(5/2)y = - 5x + 9                 multiply through by (2/5)

y = -2x + 18/5

 

m and n   are neither parallel  or perpendicular

 

Here's a graph : https://www.desmos.com/calculator/r0tsvzvdjo

 

 

cool cool cool

 Jun 8, 2019
edited by CPhill  Jun 8, 2019

18 Online Users

avatar