+0  
 
0
28
1
avatar

Given that a  is a multiple of 1428, find the greatest common divisor of a + 3 and 2a + 13.

 Oct 28, 2020
 #1
avatar
0

No matter what the value of "a" is, the GCD of  a + 3 and 2a + 13 is always = 1

 Oct 28, 2020

15 Online Users