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Circle O has center (5,5) and radius 4. Circle P has center (3,-1) and radius 5. Which describes how circle O can be transformed so that circle O is similar to circle P?

Guest Mar 10, 2017
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 #1
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All circles are similar to each other.

Guest Mar 10, 2017
 #2
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Circle O has center (5,5) and radius 4. Circle P has center (3,-1) and radius 5. Which describes how circle O can be transformed so that circle O is similar to circle P?

 

\(m=\)  \(\frac{y_o-y_p}{x_o-x_p}=\frac{5-(-1)}{5-3}\)  \(=3\)

 

\(y=mx+b\)

 

\(b=\) \(y-mx\) = \(5-3\times5\) = \(-1-3\times3\) = \(-10\)

 

\(y=3x-10\)

 

\(d=\sqrt{(y_o-y_p)^2+(x_o-x_p)^2}=\sqrt{(5-(-1))^2+(5-3)^2}=\sqrt{36+4}=\sqrt{40}\)

 

\(d=6.324555\)

 

For the conglomeration with circle O
move the circle P upwards on the straight line

y = 3x - 10

by

d = 6.324555

 

laugh  !

asinus  Mar 10, 2017

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