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# GPMA

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Circle O has center (5,5) and radius 4. Circle P has center (3,-1) and radius 5. Which describes how circle O can be transformed so that circle O is similar to circle P?

Guest Mar 10, 2017
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All circles are similar to each other.

Guest Mar 10, 2017
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Circle O has center (5,5) and radius 4. Circle P has center (3,-1) and radius 5. Which describes how circle O can be transformed so that circle O is similar to circle P?

$$m=$$  $$\frac{y_o-y_p}{x_o-x_p}=\frac{5-(-1)}{5-3}$$  $$=3$$

$$y=mx+b$$

$$b=$$ $$y-mx$$ = $$5-3\times5$$ = $$-1-3\times3$$ = $$-10$$

$$y=3x-10$$

$$d=\sqrt{(y_o-y_p)^2+(x_o-x_p)^2}=\sqrt{(5-(-1))^2+(5-3)^2}=\sqrt{36+4}=\sqrt{40}$$

$$d=6.324555$$

For the conglomeration with circle O
move the circle P upwards on the straight line

y = 3x - 10

by

d = 6.324555

!

asinus  Mar 10, 2017

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