On the graph of y = (x + 2)^2 - 10, how many points are there whose coordinates are both negative integers?
y = x2 + 4x + 4 – 10
y = x2 + 4x – 6
when x = –1, y = –9
x = –2, y = –10
x = –3, y = –9
x = –4, y = –6
x = –5, y = –1
So, there are 5 such points.
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