The lines x=(1/4)y+a and y=(1\4)x+b$ intersect at the point (1,2). What is a+b?
1. We can plug in \((1,2)\) for both equations
\(x=\frac{1}{4}y+a\rightarrow 1=\frac{2}{4}+a\rightarrow\boxed{a=\frac{1}{2}}\)
\(y=\frac{1}{4}x+b\rightarrow2=\frac{1}{4}+b\rightarrow\boxed{b=\frac{7}{4}}\)
2. Then add:
\(\frac{1}{2}+\frac{7}{4}=\boxed{\frac{9}{4}}\)
That is the answer