+0  
 
0
127
5
avatar+701 

i have no idea what im doing..

 

http://prntscr.com/l7a2x8

 Oct 17, 2018
 #1
avatar+316 
+2

Ok we have:

f(x) = x+1 , xΕ [-2,2] 

and g(x) =  x + 1 , xE [-2,1)

                  1 , x=2

                  -x + 3 , xE(1,4]

 

So f(g(x)) = (x+1) + 1 , xE [-2,1) 

                   (-x + 3) + 1 , xE (1,2] 

 

We need around 1 to know the equation of function f(g(x)) because we want lim x->1 

 

so when lim x -> 1+ f(g(x)) = (x+1) + 1 = 1 + 1 + 1 = 3 

when lim x -> 1- f(g(x)) = (-x+3) + 1 = -1 + 3 + 1 = 2 +1 = 3 so 

lim x -> 1+ = lim x -> 1- = 3 

lim x -> 1 = 3 

Correct answer (C) 

 

f(x) , g(x) I find the equation of function from graph!

 Oct 17, 2018
 #2
avatar+701 
+1

where did you get from f(x) = x+1

 

thank you !

 Oct 17, 2018
 #4
avatar+316 
+2

Because its a straight so its f(x) = ax + b 

and because x,y increase at the same rate its 1 so f(x) = x + b and b = 1 to verify the equation ! 

Dimitristhym  Oct 18, 2018
 #3
avatar+99384 
+3

here is the question

 

 

I do not understand Dimitris answer BUT

I also think that the answer is 3

as x tends to 1  g(x) tends to 2

and f(2)=3

 Oct 17, 2018
 #5
avatar+316 
+3

Yes this is the same and this is faster and i think the fastest way to answer! 

Dimitristhym  Oct 18, 2018

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