+343 Ok we have:
f(x) = x+1 , xΕ [-2,2]
and g(x) = x + 1 , xE [-2,1)
1 , x=2
-x + 3 , xE(1,4]
So f(g(x)) = (x+1) + 1 , xE [-2,1)
(-x + 3) + 1 , xE (1,2]
We need around 1 to know the equation of function f(g(x)) because we want lim x->1
so when lim x -> 1+ f(g(x)) = (x+1) + 1 = 1 + 1 + 1 = 3
when lim x -> 1- f(g(x)) = (-x+3) + 1 = -1 + 3 + 1 = 2 +1 = 3 so
lim x -> 1+ = lim x -> 1- = 3
lim x -> 1 = 3
Correct answer (C)
f(x) , g(x) I find the equation of function from graph!
+343 Because its a straight so its f(x) = ax + b
and because x,y increase at the same rate its 1 so f(x) = x + b and b = 1 to verify the equation !
+118673 here is the question
I do not understand Dimitris answer BUT
I also think that the answer is 3
as x tends to 1 g(x) tends to 2
and f(2)=3
+343 Yes this is the same and this is faster and i think the fastest way to answer!
