+0  
 
+1
53
4
avatar+194 

How many real numbers are not in the domain of the function

\(f(x) = \frac{1}{x-64} + \frac{1}{x^2-64} + \frac{1}{x^3-64}~?\)

 Apr 14, 2021
 #1
avatar+180 
+1

This means that either x-64, x^2-64, or x^3-64 is 0. so x can be 64, 8, -8, or 4 for a total of 4 solutions.

 

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 Apr 14, 2021

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