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An equilateral triangle shares a common side with a square as shown. What is the number of degrees in \(m\angle CDB\)?

 Apr 15, 2021
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Note  that  angle DCB = 90  +  60  =  150°

 

And  since DC = BC, then  triangle  DCB is isosceles with  angle CDB = angle  CBD

 

So  angle  CDB  =  (180 - 150)  / 2   =   30  / 2     =  15°    

 

 

cool cool cool

 Apr 15, 2021

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